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chitkaraankit

predict output c++

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100

 

The ## (double hash sign) operator concatenates two tokens in a macro invocation.

 

#define f(g,g2) g##g2

The given function call is f(var,12). Here,

 

g is assigned var and

g2 is assigned 12.

 

The ## operator concatenates "var" and "12" to form "var12"

 

Now, consider the printf statement :

 

printf("%d",f(var,12));

The value returned after the macro has been invoked would be "var12", and the printf statement will now be,

 

printf("%d",var12);

which in turn would print 100 as the answer, since the integer variable "var12" has been assigned the value 100.

int var12=100;

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