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Area of the park =60×40=2400=60×40=2400 m2Given that area of the lawn =2109=2109 m2∴ Total area of the cross roads =2400−2109=291=2400−2109=291 m2Assume that the width of the cross roads =x=xThen, total area of the cross roads= Area of road 11 + Area of road 22 - (Common area of the cross roads)=60x+40x−x2=60x+40x−x2 Now, we haveTotal area of cross roads =60x+40x−x2=60x+40x−x2But total area of the cross roads =291=291 m2Hence,60x+40x−x2=291⇒100x−x2=291⇒x2−100x+291=0⇒(x−97)(x−3)=0 x=3. Therefore the width of the road is 3m.

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Spatial visualization ability or visual-spatial ability is the ability to mentally manipulate 2-dimensional and 3-dimensional figures.

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The number next in the series is 34.

Start your preparation with sheer determination. Whenever you feel demotivated, you can dream about the day when you will crack the exam and it will definitely motivate you.

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The answer would be 1/365.

The destination place is 80 degree west to the starting place. Hence the time difference between these two places is 5 hour 20 min. (=24hr*80/360). When the flight landed, the time at the starting place is 12 noon (2 AM + 10 hours). Hence, the time at the destination place is 12 noon - 5:20 hours = 6: 40 AM